In this chapter, we provide RS Aggarwal Solutions for Class 6 Chapter 3 Whole Numbers Exercise 3B for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 6 Chapter 3 Whole Numbers Exercise 3B pdf, free RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Exercise 3B book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 6 |

Subject | Maths |

Chapter | Chapter 3 |

Chapter Name | Whole Numbers |

Exercise | 3B |

Category | RS Aggarwal Solutions |

**RS Aggarwal Class 6 Chapter 3 Whole Numbers Ex 3B Download PDF**

**Question 1.****Solution:**

(i) 458 + 639 = 639 + 458 (Commulative law)

(ii) 864 + 2006 = 2006 + 864 (Commulative law)

(iii) 1946 + 984 = 984 + 1946 (Commulative law)

(iv) 8063 + 0 = 8063 (Additive property of zero)

(v) 53501 + (574 + 799) = 574 + (53501 + 799) (Associative law)

**Question 2.****Solution:**

(i) 16509 + 114 = 16623

Check : 16623 – 114 = 16509 which is given.

(ii) 2359 + 548 = 2907

Check: 2907 – 2359 = 548 which is given

(iii) 19753 + 2867 = 22620

Check : 22620 – 19753 = 2867 which is given

**Question 3.****Solution:**

(1546 + 498) + 3589

= 2044 + 3589

= 5633

and 1546 + (498 + 3589)

= 1546 + 4087

= 5633

Yes, the above two sum are equal.

The property used is associative law of addition.

**Question 4.****Solution:**

(i) 953 + 707 + 647

= (953 + 647) + 707

(by associative law)

= 1600 + 707

= 2307

(ii) 1983 + 647 + 217 + 353

= (1983 + 217) + (647 + 353)

= 2200 + 1000 = 3200

(iii) 15409 + 278 + 691 + 422

= (15409 + 691) + (278 + 422)

(by associative law)

= 16100 + 700

= 16800

(iv) 3259 + 10001 + 2641 + 9999

= (3259 + 2641) + (10001 + 9999)

(by associative law)

= 5900 + 20000

= 25900

(v) 1 +2 + 3 +4 + 96 + 97 + 98 + 99

= (1 +99) + (2 + 98) + (3 + 97) + (4 + 96)

= (100+ 100) + (100 +100)

= 200 + 200

= 400

(vi) 2 + 3 + 4 + 5 + 45 + 46 + 47 + 48

= (2 + 48) + (3 + 47) + (4 + 46) + (5 + 45)

= (50 + 50) + (50 + 50)

= 100 + 100 = 209

**Question 5.****Solution:**

(i) 6784 + 9999 = (6784 – 1) + (9999 + 1)

(Adding and subtracting 1)

= 6783 + 10000

= 16783

(ii) 10578 + 99999

(Adding and subtracting 1)

= (10578 – 1) + (99999 + 1)

= 10577 + 100000

= 110577

**Question 6.****Solution:**

Yes it is true, by the property of associative law of addition.

**Question 7.****Solution:**

The magic squares given are completed as under:

In each row/column, the sum = 46

**Question 8.****Solution:**

(i) The sum of two odd numbers is an odd number (F)

As sum of two odd numbers is alway an even number

(ii) The sum of two even number is an even number (T)

(iii) The sum of an even number and an odd number is an odd number (T)

**All Chapter RS Aggarwal Solutions For Class 6 Maths**

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**All Subject NCERT Solutions For Class 6**

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